Run ID:78981

提交时间:2024-06-29 16:03:30

#include<bits/stdc++.h> using namespace std; int main(){ long long n,a1,a3,a2,a4,an; cin>>n>>a1>>a2>>a3>>a4; if(((a4-a3)==(a3-a2))&&((a4-a3)==(a2-a1))){ an=a1+(n-1)*(a2-a1); } else if(((a4/a3)==(a3/a2))&&((a4/a3)==(a3/a2))){ an=a1*pow((a4/a3),n-1); } cout<<an; return 0; }