Run ID:78976
提交时间:2024-06-29 15:56:44
#include<iostream> #include<cmath> using namespace std; int main(){ long long n,a1,a2,a3,a4,an; cin>>n>>a1>>a2>>a3>>a4; //等差数列判断 if(((a4-a3)==(a3-a2) )&&((a4-a3)==(a2-a1) )){ an = a1+(n-1)*(a2-a1); } //等比数列判断 else if(((a4/a3)==(a2/a1)) && ((a4/a3)==(a3/a2) )){ an = a1*pow((a4/a3),n-1); } cout<<an; }