Run ID:78461

提交时间:2024-06-22 09:42:33

def transpose_matrix(matrix): # 获取矩阵的行数和列数 rows, cols = len(matrix), len(matrix[0]) # 创建一个新的转置矩阵,初始化为0 transposed = [[0 for _ in range(rows)] for _ in range(cols)] # 遍历原始矩阵,填充转置矩阵 for i in range(rows): for j in range(cols): transposed[j][i] = matrix[i][j] return transposed # 读取输入的3x3矩阵 matrix = [] for _ in range(3): row = list(map(int, input().split())) matrix.append(row) # 转置矩阵 transposed_matrix = transpose_matrix(matrix) # 输出转置后的矩阵 for row in transposed_matrix: print(' '.join(f'{num}' for num in row))