Run ID:71364

提交时间:2024-04-23 10:16:01

n = int(input()) a = [[0]*n for x in range(n)] nums =[ (i,n-1-i) for i in range(n//2+1)] if n%2 \ else [ (i,n-1-i) for i in range(n//2)] # for i in range(n//2+1): # j = n-1-i # nums.append((i,j)) # print(nums) for i in range(n): for j in range(n): for t,ij in enumerate(nums): if i==ij[0] or i == ij[1] or j==ij[0] or j == ij[1]: a[i][j] = t+1 break for row in a: print(*row)