Run ID:70691

提交时间:2024-04-16 21:04:22

def ackermann(m, n): if m == 0: return n + 1 elif n == 0: return ackermann(m - 1, 1) else: return ackermann(m - 1, ackermann(m, n - 1)) m, n = map(int, input().split()) print(ackermann(m, n))