Run ID:70174

提交时间:2024-04-13 17:47:57

#include<iostream> using namespace std; int a[2001],n,s1,s2,s3,s4; char c='%'; int main(){ scanf("%d",&n); for(int i=1;i<=n;i++) scanf("%d",&a[i]); for(int i=1;i<=n;i++){ if(a[i]<=18) s1++; else if(a[i]<=35) s2++; else if(a[i]<=60) s3++; else s4++; } printf("%.2lf%c\n%.2lf%c\n%.2lf%c\n%.2lf%c",s1*1.0*100/n,c,s2*1.0*100/n,c,s3*1.0*100/n,c,s4*1.0*100/n,c); return 0; }