Run ID:63890

提交时间:2024-01-20 11:32:22

#include<iostream> using namespace std; int main(){ int k,flag=0; cin>>k; for(int x=k+1;x<=2*k;x++){ if(k*x%(x-k)==0){ int y=k*x/(x-k); printf("1/%d=1/%d+1/%d\n5",k,x,y); } } return 0; }