Run ID:163600
提交时间:2026-10-26 20:44:04
#include<iostream> using namespace std; int n1,n2,n3,n[105]; int main (){ cin>>n1; for(int g = 0;g<n1;g++){ cin>>n[g]; } cin>>n2>>n3; for(int t =n2-1; t < n2;t++){ n[t] = n3; } for(int g = 0;g<n1;g++){ cout<<n[g]<<" "; } return 0; }