Run ID:153646
提交时间:2026-05-23 16:41:31
#include<iostream> using namespace std; int main(){ int p,e,i,d; cin>>p>>e>>i>>d; int k; for(k=d+1;k<=d+21252;k++){ if((k-p)%23==0&&(k-e)%23==0&&(k-i)%23==0){ break; } } cout<<"the next triple peak occurs in "<<k-d<<" days."<<endl; return 0; }