Run ID:149039
提交时间:2026-03-06 18:48:55
#include <iostream> using namespace std; int main() { int n, k; cin >> n >> k; // 基础树苗数:起点1棵 + n米内完整的k米间隔数(n/k) int base = 1 + (n / k); // 剩余不足k米的距离 int remain = n % k; // 剩余距离>1米则额外+1,否则+0 int extra = (remain > 1) ? 1 : 0; int total = base + extra; cout << total << endl; return 0; }