Run ID:14898

提交时间:2021-07-08 19:02:19

#include <iostream> using namespace std; int a[105]; int main() { int n; cin >> n; int *p = a; for (int i = 1; i <= n; i++) { cin >> *(p + i); if (*(p + i) % 2 == 0) { cout << *(p + i) - 1 << " "; } else { cout << *(p + i) + 1 << " "; } } return 0; }