Run ID:148789
提交时间:2026-02-28 19:46:50
#include <iostream> using namespace std; int main() { int n; cin >> n; long long result; if (n <= 2) { result = 1; } else { result = 1 + (long long)(n-2) * (n-1) / 2; } cout << result << endl; return 0; }