Run ID:148362
提交时间:2026-02-11 13:57:53
#include<iostream> using namespace std; int main(){ int k=0; cin>>k; for(int x=k+1;x<=2*k;x++){ int a=k*x; int b=x-k; int y=a/b; if(1/k==1/y+1/x&&a%b==0){ cout<<"1/"<<'k'<<'='<<"1/"<<'x'<<'+'<<"1/"<<'y'<<endl; } } return 0; }