#include <iostream> #include <sstream> #include <ctime> // 判断是否为闰年 bool isLeapYear(int year) { return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0); } int main() { int T; std::cin >> T; while (T--) { std::string dateStr; std::cin >> dateStr; int year, month, day; sscanf(dateStr.c_str(), "%d-%d-%d", &year, &month, &day); int targetYear = year + 18; if ((month == 2 && day == 29 &&!isLeapYear(targetYear))) { std::cout << -1 << std::endl; continue; } int days = 0; for (int i = year; i < targetYear; ++i) { days += isLeapYear(i)? 366 : 365; } // 这里直接假设不满一年的天数为0，因为如果是同一天，差值就是0，不需要复杂时间函数计算 std::cout << days << std::endl; } return 0; }