//1530 x的n次方 #include<iostream> #include<cstdio> #include<cstring> #include<cmath> using namespace std; int use(int x,int n){ int s=0; if(n==1){ return x; } x*=x; n-=1; return use(x,n); } int main(){ int n,m; cin>>n>>m; cout<<use(n,m); return 0; }