Run ID:142427
提交时间:2026-01-09 18:49:50
//1528 n的阶乘(递归) #include<iostream> #include<cstdio> #include<cstring> #include<cmath> using namespace std; int use(int n){ int s=0,a=1; if(n==1){ return 1; } return n*use(n-1); } int main(){ int n; cin>>n; cout<<use(n); return 0; }