#include <iostream> using namespace std; int main() { int p, e, i, d; cin >> p >> e >> i >> d; int p_mod = p % 23; int e_mod = e % 28; int i_mod = i % 33; for (int x = d + 1; x <= 21252; x++) { if (x % 23 == p_mod && x % 28 == e_mod && x % 33 == i_mod) { cout << x - d << endl; return 0; } } // 题目保证有解，此部分不会执行 cout << 0 << endl; return 0; }