Run ID:133916

提交时间:2025-10-25 10:18:25

#include<iostream> #include<math.h> #include<string.h> using namespace std; double fb(double x, double n){ if(n == 1){ return x * 1.0 / (1 + x) * 1.0; // 装换 }else{ return x * 1.0 / (n + fb(x, n-1)); } } int main(){ double n, x; double ans; scanf("%lf %lf", &x, &n); ans = fb(x, n); printf("%.2lf", ans); return 0; }