Run ID:127905

提交时间:2025-07-30 12:31:01

#include<bits/stdc++.h> using namespace std; int main() { //只需要按照求数组总和的方式 int n, m; cin >> n >> m; int a[5][5]; for (int i = 0; i < 5; i++) { for (int j = 0; j < 5; j++) { cin >> a[i][j]; } } int t; t = a[n - 1][0] ; a[n - 1][0] = a[m - 1][0]; a[m - 1][0] = t; t = a[n - 1][1] ; a[n - 1][1] = a[m - 1][1]; a[m - 1][1] = t; t = a[n - 1][2] ; a[n - 1][2] = a[m - 1][2]; a[m - 1][2] = t; t = a[n - 1][3] ; a[n - 1][3] = a[m - 1][3]; a[m - 1][3] = t; t = a[n - 1][4] ; a[n - 1][4] = a[m - 1][4]; a[m - 1][4] = t; for (int i = 0; i < 5; i++) { for (int j = 0; j < 5; j++) { cout<< a[i][j]<<" "; } cout<<endl; } return 0; }