Run ID:127313

提交时间:2025-07-27 09:39:26

n = int(input()) matrix = [] for _ in range(n): row = list(map(int, input().split())) matrix.append(row) # 检查每一行的1的个数是否为偶数 row_ok = True for row in matrix: if sum(row) % 2 != 0: row_ok = False break if row_ok == True: # 检查每一列的1的个数是否为偶数 col_ok = True for j in range(n): col_sum = 0 for i in range(n): col_sum += matrix[i][j] if col_sum % 2 != 0: col_ok = False break if not row_ok or not col_ok: print("Corrupt") else: print("OK")