Run ID:126600
提交时间:2025-07-21 13:05:10
#include<bits/stdc++.h> using namespace std; int main() { //数组 int n; cin >> n; int a[n]; for (int i = 0; i < n; i++) { cin >> a[i]; } float sum = 0;//累加器初始化为0 float p = sum * 1.0 / n; printf("% .2f\n", p); return 0; }