#include<iostream> #include<cstring> #include<cmath> using namespace std; int main(){ int i=0; char a[64]; cin>>a; int len=strlen(a); double sum=0; while(a[i]!='.') { i++; } for(int j=i-1,k=0;j>=0;k++,j--){ sum+=((a[j]-'0')*pow(2,k)); } int c=-1; for(i+=1;i<len;i++){ sum+=((a[i]-'0')*pow(2,c)); c--; } cout<<sum; return 0; }