Run ID:112822
提交时间:2025-03-13 20:41:27
#include<iostream> using namespace std; int a[10000]; int main(){ int n,max,min,i; double p=0,z=0; max=0; min=10000; cin>>n; for(i=1;i<=n;i++){ cin>>a[i]; z=z+a[i]; for(int j=1;j<=a[i];j++){ if(a[i]<min){ min=a[i]; } else if(a[i]>max){ max=a[i]; } } } cout<<z<<" "; printf("%.2lf",z/n); cout<<" "<<max<<" "<<min; return 0; }