Run ID:109886

提交时间:2025-02-13 11:07:15

#include <iostream> using namespace std; int main(){ int k; cin>>k; for(int i=k+1;i<=2*k;i++) { int j; j = k*i/ ( i-k); if( k*i % (i-k) == 0) cout<< "1/"<<k<<" = 1/"<<i<<" + 1/"<<j<<endl; } return 0; } /* Input 5 Output 1/5 = 1/6 + 1/30 1/5 = 1/10 + 1/10 for(int x=k+1;x<=2*k;x++) { int y=k*x/(x-k); if(k* x%(x-k) ==0 ) cout<<"1/"<<k<<" = 1/"<<x<<" + 1/"<<y<<endl; } */