Run ID:107460

提交时间:2025-01-17 22:07:34

#include <iostream> using namespace std; int main () { int k; cin>>k; for(int x=k+1;x<=2*k;x++) { int y=k*x/(x-k); if(k* x%(x-k) ==0 ) cout<<"1/"<<k<<" = 1/"<<x<<" + 1/"<<y<<endl; } return 0; }