Run ID:100248
提交时间:2024-12-07 12:00:36
#include<iostream> using namespace std; int main(){ int n,i;=10000,j=10000,k; cin>>n; for(k=1;k<=(n-1)/2;k++) { i--; j-=2; } if(n%2) cout<<i<<endl; else cout<<j<<endl; return 0; }