Run ID 作者 问题 语言 测评结果 Time Memory 代码长度 提交时间
88704 判断三角形形状 Python3 Accepted 38 MS 3792 KB 356 2024-08-20 15:52:03

Tests(1/1):


Code:

t = int(input()) s = [] for i in range(t): a,b,c = input().split() a,b,c = int(a),int(b),int(c) if a == b or a == c or b == c: s.append('perfect') elif a**2 + b**2 == c**2 or a**2 + c**2 == b**2 or c**2 + b**2 == a**2: s.append('good') else: s.append('just a triangle') for i in s: print(i)