Run ID | 作者 | 问题 | 语言 | 测评结果 | Time | Memory | 代码长度 | 提交时间 |
---|---|---|---|---|---|---|---|---|
79343 | 彭士宝 | 数组转置 | Python3 | Accepted | 32 MS | 3780 KB | 665 | 2024-07-03 21:15:14 |
def transpose_matrix(matrix): # 获取矩阵的行数和列数 n = len(matrix) # 创建一个新的转置矩阵,初始化为零矩阵 transposed = [[0 for _ in range(n)] for _ in range(n)] # 遍历原矩阵,填充转置矩阵 for i in range(n): for j in range(n): transposed[j][i] = matrix[i][j] return transposed # 读取输入 matrix = [] for _ in range(3): row = list(map(int, input().split())) matrix.append(row) # 调用函数进行转置 transposed_matrix = transpose_matrix(matrix) # 输出转置后的矩阵 for row in transposed_matrix: print(" ".join(map(str, row)))