Run ID | 作者 | 问题 | 语言 | 测评结果 | Time | Memory | 代码长度 | 提交时间 |
---|---|---|---|---|---|---|---|---|
45064 | 木木老师 | 相对分子质量 | Python3 | Accepted | 31 MS | 3780 KB | 390 | 2023-03-05 14:08:02 |
n=int(input()) l=[] d={"H":1,"C":12,"N":14,"O":16,"F":19,"P":31,"S":32,"K":39} for i in range (n): m=input() l.append(m) for i in l: count=0 t=0 for j in range (len(i)): if i[j] in d: if t!=0: count+=t t=d[i[j]] else: count+=t*int(i[j]) t=0 count+=t print(count)