| Run ID | 作者 | 问题 | 语言 | 测评结果 | Time | Memory | 代码长度 | 提交时间 |
|---|---|---|---|---|---|---|---|---|
| 147073 | 赖泓宇 | 04保留两位小数 | C++ | Wrong Answer | 0 MS | 272 KB | 343 | 2026-02-02 16:58:06 |
#include<iostream> // cin\cout\endl #include<cstdio> //scanf()\printf() #include<cstring> // strcpy()\strcat()\strcmp()\strlen()\memset() #include<iomanip> #include<cmath> //sqrt()\pow()\abs()\ceil()\floor()\max()\min() using namespace std; int main(){ double a,b; cin>>a>>b; printf("%.7lf %.2lf",a/b); }
------Input------
0 8
------Answer-----
0.00
------Your output-----
0.0000000 -179769313486231570814527423731704356798070567525844996598917476803157260780028538760589558632766878171540458953514382464234321326889464182768467546703537516986049910576551282076245490090389328944075868508455133942304583236903222948165808559332123348274797826204144723168738177180919299881250404026184124858368.00