| Run ID | 作者 | 问题 | 语言 | 测评结果 | Time | Memory | 代码长度 | 提交时间 |
|---|---|---|---|---|---|---|---|---|
| 136719 | 鸡哥 | 数组中元素交换 | C++ | Wrong Answer | 2 MS | 268 KB | 217 | 2025-11-15 15:06:04 |
#include<bits/stdc++.h> using namespace std; int main(){ int a[21]; for(int i = 1;i<=20;i++){ cin>>a[i]; } for(int i = 20;i>=1;i--){ cout<<"N["<<20-i<<"] = "<<a[i]<<endl; } return 0; }
------Input------
1 49
------Answer-----
49
------Your output-----
N[0] = 441165736 N[1] = 0 N[2] = 1 N[3] = 0 N[4] = 8 N[5] = 0 N[6] = 4197296 N[7] = 0 N[8] = 0 N[9] = 0 N[10] = 9 N[11] = 32767 N[12] = 441165752 N[13] = 0 N[14] = 32768 N[15] = 0 N[16] = 1 N[17] = 0 N[18] = 49 N[19] = 1