| Run ID | 作者 | 问题 | 语言 | 测评结果 | Time | Memory | 代码长度 | 提交时间 |
|---|---|---|---|---|---|---|---|---|
| 127524 | 丁海扬 | 图像相似度 | C++ | Wrong Answer | 2 MS | 304 KB | 321 | 2025-07-28 13:47:17 |
#include<bits/stdc++.h> using namespace std; int main() { int a[100][100],b[100][100],m,n,sum=0; cin>>n>>m; for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) { cin>>a[i][j]; cin>>b[i][j]; if(a[i][j]==b[i][j]) sum+=1; } printf("%.2f",sum*1.0/(m*n)*100); return 0; }
------Input------
30 20 0 1 1 0 0 0 0 1 0 1 0 0 1 1 0 1 1 1 0 1 0 0 0 0 1 0 1 0 1 1 0 1 1 0 1 1 0 1 0 0 0 0 0 0 0 0 0 1 0 1 1 0 1 1 1 1 1 1 1 1 0 0 0 0 1 1 0 1 1 0 0 1 0 1 0 0 0 1 1 1 0 1 1 1 1 0 1 0 1 1 0 1 1 0 0 0 1 0 0 0 0 0 1 0 1 1 1 0 1 1 1 0 1 0 1 0 1 0 1 1 0 1 0 0 0 0 0 1 0 1 0 0 0 0 0 1 1 0 0 0 1 1 0 0 0 1 1 1 1 0 0 0 1 0 0 0 0 1 1 0 0 1 1 1 1 0 0 0 0 1 1 1 1 0 1 0 1 1 0 0 1 1 1 1 0 1 0 1 1 1 0 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 0 0 0 0 1 0 1 0 0 0 1 1 1 1 1 0 0 0 1 0 0 1 1 0 1 1 1 1 1 1 0 1 1 0 0
------Answer-----
48.17
------Your output-----
50.17