| Run ID | 作者 | 问题 | 语言 | 测评结果 | Time | Memory | 代码长度 | 提交时间 |
|---|---|---|---|---|---|---|---|---|
| 122861 | 杜春雨 | 只出现一次的字符 | C++ | Wrong Answer | 0 MS | 284 KB | 549 | 2025-06-21 17:08:29 |
#include<iostream> // cin\cout\endl #include<cstdio> //scanf()\printf() #include<cstring> // strcpy()\strcat()\strcmp()\strlen()\memset() #include<cmath> //sqrt()\pow()\abs()\ceil()\floor()\max()\min() using namespace std; int main(){ int a[26]={0}; string x; getline(cin,x); for(int i=0;i<x.length();i++){ a[x[i]-'a']; } for(int i=0;i<x.length();i++){ if(a[x[i]-'a']==1){ cout<<x[i]<<endl; return 0; } } cout<<"no"<<endl; return 0; }
------Input------
okijdwkbqvdcjvxofevfgosohbkpcxuwdbnejhfeyvlqftqxjkbnjlounwzdtyveeehsmdgjkppezfdudxgvlulmxveqhupzpjnncimikhqxovuebjqqqjxbfuugbetcxquxobzngbrythjxkufscjmwccypyrctblzwdpwujplnrkfrezjqfdlmdrflzleflmqyduwupcyebmokpwzgbvkzielyqorbmelvbusfyfkixiulsbsjblbdogkvdklevovqsgcipgooppcjouetskhfiiqffkfywtoggklrzbpitpyyswttddpyccehltnnrogsebvpiyvqwunenehsbpwnislmjedhillmyhluztremcgrvxxidbhyjpbnccvgtwfngzruxjrregvioocdchpygfkenmxbnqonrrqjodopqgzsvqqrrjqwhzvlsidhkimtspmmvunxhxrwkoretblpcwwwjfiuujrveuxvyskcfmvsyqss
------Answer-----
a
------Your output-----
no