Run ID | 作者 | 问题 | 语言 | 测评结果 | Time | Memory | 代码长度 | 提交时间 |
---|---|---|---|---|---|---|---|---|
106796 | 罗迎甲 | 两个数的最小距离II | C++ | Wrong Answer | 1 MS | 280 KB | 608 | 2025-01-16 16:33:45 |
#include <iostream> #include <cmath> #include <cstdio> using namespace std; long long a[1005]; int main() { /* freopen("a.in", "r", stdin); freopen("a.out", "w", stdout); */ int n; long long t; cin >> n; for (int i = 1; i <= n; i++) { cin >> a[i]; } long long min = abs (a[1] - a[2]); for (int i = 1; i <= n; i++) { for (int j = i + 1; j <= n; j++) { t = abs(a[i] - a[j]); if (t < min) { min = t; } } } cout << min; return 0;}
------Input------
940 758926704 -960964048 -430141843 468532242 -880373592 683061267 519316474 147051688 719416223 901294929 930598316 344190816 -909295224 -703928603 982691789 -532274625 -865094105 -608855024 -180757338 -910192517 -725725557 -770344534 -56909888 323802311 -981526148 876907807 -238812122 904848323 -118180751 113460304 -343347383 -148747218 453083382 -135336696 -516925037 646757862 183906743 -276943828 -386044671 422454212 -202786322 -475659031 -893786081 -365403011 748358874 460671925 334228484 1
------Answer-----
357 665
------Your output-----
2545