Run ID 作者 问题 语言 测评结果 Time Memory 代码长度 提交时间
103904 汤奕硕 数组逆置 C Wrong Answer 1 MS 196 KB 478 2025-01-01 14:35:34

Tests(0/1):

Code:

#include <stdio.h> #include <string.h> int main() { char str[201]; // 假设字符串长度最大为200，额外一个字符用于存储'\0' while (scanf("%200s", str) != EOF) { // 读取字符串，最大长度为200 int len = strlen(str); // 获取字符串长度 for (int i = len - 1; i >= 0; --i) { // 逆置输出字符串 putchar(str[i]); } putchar('\n'); // 每组输出后换行 } return 0; }

Run Info:

------Input------

tianqin
*xd):0gP^""vYq jdcU%b^A,h1scE6#Sb+W|tKtC!&!ZHbBtBPD,[&M#gpGpnhMgq/A')Px,]}T6Hoe/x"kZ
(OAXg|!aat%YG;@e9@b^K~AF{/2_q*vw61:){XM7]7jt\Xr(yRwKkyM^$=&0zUVc),B[c79@/Xt+v\+mOJKN'rk %D4u[a"%Bd#-,4s}$LM%l
J$R?nrxte7'/ZVKK$#:+sDYoB`>j+2G~0:@wH=`^q-?yN0cUS](94=6L5uX|O;V`3,B/uJK@3HZ:jLrcIP8%gLsi`X3a!WKs,/o^U";-nqNO0w)dF@;Iq}wvD3RNUYby$W/;hRR?9r ~KQ=lkii\Uz $CI6nmwR&:Ah_O*#@l81o' @|mh
+iEL;n-.4[?jdEa D_j@M}cS s#;'7b~heF"@;QwE0EiN4\+G>G!=0/ER}<'Sp'qKGD_/7.T>t(ljA3nK2n>Ai#(0yA~w0KIrNX[[)"9B9?~Ycv:
------Answer-----

niqnait
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hm|@ 'o18l@#*O_hA:&Rwmn6IC$ zU\iikl=QK~ r9?RRh;/W$ybYUNR3Dvw}qI;@Fd>c<)w0ONqn-;"U^o/,sKW!a3X`isLg%8PIcrLj:ZH3@KJu/B,3`V;O|Xu5L6=49(]SUc0Ny?-q^`=Hw@:0~G2+j>`BoYDs+:#$KKVZ/'7etxrn?R$J
a%}`r3D2aRe~r}@A+[AP>:vcY~?9B9")[[XNrIK0w~Ay0(#iA>n2Kn3Ajl(t>T.7/_DGKq'pS'<}RE/0=!G>G+\4NiE0EwQ;@"Feh~b7';#s Sc}
------Your output-----

niqnait
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l%ML$}s4,-#dB%"a[u4D%
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