刘世杰 • 7个月前
#include <iostream>
using namespace std;
int a[105][105];
int main() {
int n, m;
cin >> n >> m;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
cin >> a[i][j];
}
}
for (int i = 0; i < n; i++) {
if (a[i][i] == a[i][n - 1 - i]) {
a[i][i] += m;
continue;
}
a[i][i] += m;
a[i][n - 1 - i] += m;
}
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
printf("%5d", a[i][j]);
}
cout << endl;
}
return 0;
}
评论: