王乾源 • 4年前
评论:
#include <iostream> #include <cmath> #include <cstdio> using namespace std; long long a[1005]; int main() { /* freopen("a.in", "r", stdin); freopen("a.out", "w", stdout); */ int n; long long t; cin >> n; for (int i = 1; i <= n; i++) { cin >> a[i]; } long long min = abs (a[1] - a[2]); for (int i = 1; i <= n; i++) { for (int j = i + 1; j <= n; j++) { t = abs(a[i] - a[j]); if (t < min) { min = t; } } } cout << min; return 0; }
自己换行