@王乾源

#include <iostream>

using namespace std;

int a[105][105];

int main() {

int n, m;

cin >> n >> m;

for (int i = 0; i < n; i++) {

for (int j = 0; j < n; j++) {

cin >> a[i][j];

}

}

for (int i = 0; i < n; i++) {

if (a[i][i] == a[i][n - 1 - i]) {

a[i][i] += m;

continue;

}

a[i][i] += m;

a[i][n - 1 - i] += m;

}

for (int i = 0; i < n; i++) {

for (int j = 0; j < n; j++) {

printf("%5d", a[i][j]);

}

cout << endl;

}

return 0;

}

AC代码（不得不说这是真的简单）